A) \[5\times {{10}^{-4}}mol\text{ }{{L}^{-1}}{{s}^{-1}}\]
B) \[5\times {{10}^{-5}}mol\,{{L}^{-1}}{{s}^{-1}}\]
C) \[6\times {{10}^{-5}}mol\,{{L}^{-1}}{{s}^{-1}}\]
D) \[4\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]
Correct Answer: A
Solution :
Increase in concentration of \[B=5\times {{10}^{-3}}mol\,{{L}^{-1}}\] Time = 10 s \[Rate\text{ }of\text{ }appearance\text{ }of\text{ }B=\frac{increase\text{ }of\text{ }cone.\text{ }B}{time\text{ }taken}\] \[=\frac{5\times {{10}^{-3}}mol\,{{L}^{-1}}}{10s}=5\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]
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