A) chloromethane
B) iodoform
C) carbon tetrachloride
D) chloroform
Correct Answer: C
Solution :
Compound is carbon tetrachloride because\[CC{{l}_{4}}\]has\[s{{p}^{3}}\]hybridisation, 4 orbitals give regular tetrahedron geometry. In other choices the geometry is little distorted inspite of\[s{{p}^{3}}\]hybridisation due to different atoms on the vertices of tetrahedron.
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