BHU PMT BHU PMT (Screening) Solved Paper-2007

  • question_answer
    A bar magnet is oscillating in the earth's magnetic field with a period T. What happens to its period and motion if its mass is quadrupled?

    A) Motion remains SH with time period = 4T

    B)  Motion remains SH and period remains nearly constant

    C)  Motion remains SH with time period\[=\frac{T}{2}\]

    D)  Motion remains SH with time period\[=2T\]

    Correct Answer: D

    Solution :

                     The time period will be \[T=2\pi \sqrt{\left| \frac{\theta }{\alpha } \right|}=2\pi \sqrt{\frac{I}{MH}}\] or            \[T\propto \sqrt{I}\] or            \[T\propto \sqrt{m}\]    \[\left( \therefore I=\frac{m{{l}^{2}}}{12} \right)\] \[\therefore \]  \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}}\] or            \[{{T}_{2}}=2T\]


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