BHU PMT BHU PMT (Screening) Solved Paper-2007

  • question_answer
    The product obtained, heating ethanol with cone.\[{{H}_{2}}S{{O}_{4}}\]at\[165{}^\circ C-170{}^\circ C,\]is

    A)  \[{{({{C}_{2}}{{H}_{5}})}_{2}}S{{O}_{4}}\]            

    B) \[C{{H}_{3}}COOH\]

    C)   \[C{{H}_{2}}=C{{H}_{2}}\]          

    D) \[{{C}_{2}}{{H}_{5}}HS{{O}_{4}}\]

    Correct Answer: C

    Solution :

                     Ethyl alcohol, on heating at\[165{}^\circ -170{}^\circ C\]with cone.\[{{H}_{2}}S{{O}_{4}}\]gives ethylene. \[{{C}_{2}}{{H}_{5}}OH\xrightarrow[{{170}^{o}}C]{conc.\,{{H}_{2}}S{{O}_{4}}}\underset{ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,+{{H}_{2}}O\]


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