A) 1.6
B) 1.2
C) 4.8
D) 3.5
Correct Answer: B
Solution :
The efficiency of heat engine is\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] Or \[\frac{W}{{{Q}_{1}}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\] Here,\[{{Q}_{1}}=\]heat absorbed from the source of heat = 6 kcal \[{{T}_{1}}=\]temperature of source \[=227+273=500\text{ }K\] and\[{{T}_{2}}=\] temperature of sink \[=127+273=400\text{ }K\] Hence, \[\frac{W}{6}=1-\frac{400}{500}\] Or \[\frac{W}{6}=\frac{100}{500}\]or \[W=1.2\,kcal\] Thus, amount of heat converted into work is \[1.2\,kcal\].You need to login to perform this action.
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