A) Motion remains SH with time period = 4T
B) Motion remains SH and period remains nearly constant
C) Motion remains SH with time period\[=\frac{T}{2}\]
D) Motion remains SH with time period\[=2T\]
Correct Answer: D
Solution :
The time period will be \[T=2\pi \sqrt{\left| \frac{\theta }{\alpha } \right|}=2\pi \sqrt{\frac{I}{MH}}\] or \[T\propto \sqrt{I}\] or \[T\propto \sqrt{m}\] \[\left( \therefore I=\frac{m{{l}^{2}}}{12} \right)\] \[\therefore \] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}}\] or \[{{T}_{2}}=2T\]You need to login to perform this action.
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