A) connecting two in series and one in parallel
B) connecting two in parallel and one in series
C) connecting all of them in series
D) connecting all of them in parallel
Correct Answer: A
Solution :
Key Idea: In series order, the net capacitance is, \[\frac{1}{C}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}+.......\] In parallel order, the net capacitance is, \[C={{C}_{1}}+{{C}_{2}}+{{C}_{3}}+.....\] We have given, \[{{C}_{1}}={{C}_{2}}={{C}_{3}}=4\mu F\] The network of three capacitors is shown.You need to login to perform this action.
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