A) 3.70 g
B) 6.30 g
C) 1.35 g
D) 2.50 g
Correct Answer: C
Solution :
Mean life, \[\tau =\frac{1}{\lambda },\lambda \]being decay constant. Also time given, \[\tau =2\tau =2\times \frac{1}{\lambda }=\frac{2}{\lambda }\] Thus, mass remained after time t is \[M={{M}_{0}}{{e}^{-\lambda t}}\] \[=10{{e}^{-\lambda \times \frac{2}{\lambda }}}\] \[(\because {{M}_{0}}=10g)\] \[=10{{e}^{-2}}=\frac{10}{{{e}^{2}}}=1.35\,g\]
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