A) \[{{10}^{10}}\]
B) \[{{10}^{15}}\]
C) \[{{10}^{1}}\]
D) \[{{10}^{5}}\]
Correct Answer: B
Solution :
\[Radius\text{ }of\text{ }atom\approx {{10}^{-10}}m\] \[Radius\text{ }of\text{ }nucleus\approx {{10}^{-15}}m\] \[Required\text{ }ratio=\frac{volume\text{ }of\text{ }atom}{volume\text{ }of\text{ }nucleus}\] \[=\frac{\frac{4}{3}\pi r_{1}^{3}}{\frac{4}{3}\pi r_{2}^{3}}\] \[={{\left( \frac{{{10}^{-10}}}{{{10}^{-15}}} \right)}^{3}}={{10}^{15}}\]
You need to login to perform this action.
You will be redirected in
3 sec
