A) \[Wb/{{m}^{2}}\]
B) Henry (H)
C) \[H/{{m}^{2}}\]
D) Weber (Wb)
Correct Answer: B
Solution :
Magnetic energy \[=\frac{1}{2}L{{i}^{2}}=\frac{L{{Q}^{2}}}{2{{t}^{2}}}\] [\[L\to \]inductance,\[i\to \]current ] Energy has the dimensions\[[M{{L}^{2}}{{T}^{-2}}]\] Equate the dimensions, we have \[[M{{L}^{2}}{{T}^{-2}}]=henry\times \frac{[{{Q}^{2}}]}{[{{T}^{2}}]}.\] \[\Rightarrow \] \[henry=\frac{[M{{L}^{2}}]}{[{{Q}^{2}}]}\]
You need to login to perform this action.
You will be redirected in
3 sec
