2. Solved Papers
  3. BHU PMT

BHU PMT BHU PMT (Screening) Solved Paper-2007

  • question_answer
    For driving current of 2 A for 6 min in a circuit, 1000J of work is to be done. The emf of the source in the circuit is

    A)  1.38V                                   

    B)  1.68V

    C)  2.03V                                   

    D)  3.10V

    Correct Answer: A

    Solution :

                     If\[i\]is the current in a wire then the charge flown through the wire in t sec is \[q=it\] \[=2\times 6\times 60=720C\] The work done in taking q coulomb (720 C) of charge from one end of wire to other end under a potential difference of V volts (in this case emf) is \[W=V.q\Rightarrow V=\frac{W}{q}=\frac{1000}{720}=1.38\,V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner