BHU PMT BHU PMT (Screening) Solved Paper-2007

  • question_answer
    Speed of a ball of 2 cm radius in a viscous liquid is 20 cm/s. Then the speed of 1 cm radius of ball in the same liquid is

    A)  80 cm/s                              

    B)  40 m/s

    C)  10 cm/s                              

    D)  5 cm/s

    Correct Answer: D

    Solution :

                     Since, ball is moving with a constant speed v, there is no acceleration in it, the net force acting on it, must be zero. That is, \[6\pi \eta rv=\frac{4}{3}\pi {{r}^{3}}(\rho -\sigma )g\] \[\Rightarrow \]               \[v=\frac{2}{9}\frac{{{r}^{2}}(\rho -\sigma )g}{\eta }\] \[\Rightarrow \]               \[v\propto {{r}^{2}}\] Here, \[{{v}_{1}}=20\,cm/s.\]\[{{r}_{1}}=2\,cm,\]\[{{r}_{2}}=1\,cm\] \[\therefore \]  \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{20}{{{v}_{2}}}=\frac{{{(2)}^{2}}}{{{(1)}^{2}}}\]


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