BHU PMT BHU PMT (Screening) Solved Paper-2007

  • question_answer
    The vector sum of two forces is perpendicular to their vector difference. In that case, the forces

    A)  are not equal to each other in magnitude

    B)  cannot be predicted

    C)  are equal to each other

    D)  are equal to each other in magnitude

    Correct Answer: D

    Solution :

                     Key Idea: The two vectors must be perpendicular if their dot product must be zero. Let\[\overrightarrow{A}\]and\[\overrightarrow{B}\]be two forces. The sum of the two forces, \[{{\overrightarrow{F}}_{1}}=\overrightarrow{A}+\overrightarrow{B}\]               ...(i) The difference of the two forces, \[{{\overrightarrow{F}}_{2}}=\overrightarrow{A}-\overrightarrow{B}\]                    ...(ii) Since, sum of the two forces is perpendicular to their difference as said, so                 \[{{\overrightarrow{F}}_{1}}.{{\overrightarrow{F}}_{2}}=0\] Or           \[(\overrightarrow{A}+\overrightarrow{B}).(\overrightarrow{A}-\overrightarrow{B})=0\] Or           \[{{A}^{2}}-\overrightarrow{A}.\overrightarrow{B}+\overrightarrow{B}.\overrightarrow{A}-{{B}^{2}}=0\] Or           \[{{A}^{2}}={{B}^{2}}\] Or           \[|\overrightarrow{A}|=|\overrightarrow{B}|\] Thus, the forces are equal to each other in magnitude.


You need to login to perform this action.
You will be redirected in 3 sec spinner