BHU PMT BHU PMT (Screening) Solved Paper-2007

  • question_answer
    The number of unpaired electron in\[M{{n}^{2+}}\]is

    A)  4                                            

    B)  5

    C)  6                                            

    D)  7

    Correct Answer: B

    Solution :

                     \[Mn=(25)=3{{d}^{5}}4{{s}^{2}}\] \[M{{n}^{2+}}=\] Five unpaired electrons are present in d subshell of\[M{{n}^{2+}}\].


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