A) \[1{{s}^{2}},\text{ }2{{s}^{2}}\]
B) \[3{{d}^{10}},\text{ }4{{s}^{2}},4{{p}^{2}}\]
C) \[1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}}\]
D) \[1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{2}},\text{ }3{{s}^{1}}\]
Correct Answer: D
Solution :
\[1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{2}},\text{ }3{{s}^{1}}\]configuration is not possible because electron cannot goes in 3s orbital without filling 2p subshell.
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