A) \[C{{H}_{3}}Cl\]
B) \[{{C}_{2}}{{H}_{5}}Cl\]
C) \[CC{{l}_{3}}.CHO\]
D) \[CHC{{l}_{3}}\]
Correct Answer: D
Solution :
When ethyl alcohol reacts with chlorine gas in presence of\[NaOH,\]the product will be chloroform \[{{C}_{2}}{{H}_{5}}OH+C{{l}_{2}}\xrightarrow[\Delta ]{NaOH}CHC{{l}_{3}}\]
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