BHU PMT BHU PMT (Screening) Solved Paper-2007

  • question_answer
    The electronic configuradon of nitrogen can be expressed as

    A)  \[1{{s}^{2}},2{{s}^{2}},2p_{x}^{2},p_{y}^{1}p_{z}^{0}\]

    B)  \[1{{s}^{2}},2{{s}^{2}},2p_{x}^{1},p_{y}^{1},p_{z}^{1}\]

    C)  \[1{{s}^{2}},2{{s}^{2}},2p_{x}^{3},p_{y}^{0},p_{z}^{0}\]

    D)  \[1{{s}^{2}},2{{s}^{2}},2p_{x}^{1},p_{y}^{2},p_{z}^{0}\]

    Correct Answer: B

    Solution :

                     Nitrogen   (7),  electronic  configuration\[=1{{s}^{2}},2{{s}^{2}},2p_{x}^{1},2p_{y}^{1},2p_{z}^{1}\] Note: According Hund?s rule. "Pairing of electrons in various orbitals (like\[{{p}_{x}},{{p}_{y}},{{p}_{z}}\]) of a suborbit like (np) take place only after each orbital is half filled/singly occupied".


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