A) \[1.3\times {{10}^{-20}}g\]
B) \[5.01\times {{10}^{-21}}g\]
C) \[3.72\times {{10}^{13}}g\]
D) \[1.4\times {{10}^{-21}}g\]
Correct Answer: D
Solution :
The molecular weight of\[{{C}_{60}}{{H}_{122}}=60\times 12+122=720+122=842\] The weight of one molecule of\[{{C}_{60}}{{H}_{122}}=\]molecular wt. of compound/Avogadro number \[=\frac{842}{6.023\times {{10}^{23}}}\] \[=1.4\times {{10}^{-21}}g\]
You need to login to perform this action.
You will be redirected in
3 sec
