BHU PMT BHU PMT (Screening) Solved Paper-2008

  • question_answer
    Three blocks of masses\[{{m}_{1}},{{m}_{2}}\]and\[{{m}_{3}}\]kg are placed in contact with each other on a frictionless table. A force F is applied on the heaviest mass\[{{m}_{1}};\]the acceleration of\[{{m}_{3}}\]will be

    A)  \[\frac{F}{{{m}_{1}}}\]                                 

    B)  \[\frac{F}{{{m}_{1}}+{{m}_{2}}}\]

    C)  \[\frac{F}{{{m}_{2}}+{{m}_{3}}}\]                           

    D)  \[\frac{F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\]

    Correct Answer: D

    Solution :

                     The acceleration of mass\[{{m}_{3}}\]= common acceleration of the system \[=\frac{force\text{ }applied}{total\text{ }mass}\] \[=\frac{F}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\]


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