A) 317 m/s
B) 635 m/s
C) 830 m/s
D) 950 m/s
Correct Answer: B
Solution :
As total energy remains conserved in SHM, hence when U is maximum in SHM,\[K=0,\]ie, E is also equal to\[{{U}_{\max }},ie,{{U}_{\max }}=E={{K}_{0}}\] As given, the volumes of hydrogen and oxygen in a mixture is 4 1, so let V be the volume of oxygen. The volume of hydrogen will be 4 V. If\[{{\rho }_{m}}\]be the density of mixture, then \[{{\rho }_{m}}=\frac{4V\times 1+V\times 16}{5V}=4\] As \[v\propto {{\left( \frac{1}{\rho } \right)}^{1/2}}\] \[\therefore \]Velocity in mixture\[=\frac{1270}{{{(4)}^{1/2}}}=635\text{ }m/s\]
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