BHU PMT BHU PMT (Screening) Solved Paper-2008

  • question_answer
    Which of the following is incorrect?

    A)  Functional isomerism is shown by \[C{{H}_{3}}C{{H}_{2}}OH\text{ }and\text{ }C{{H}_{3}}OC{{H}_{3}}\]

    B)  \[H-\underset{\begin{smallmatrix}  | \\  H \end{smallmatrix}}{\overset{\begin{smallmatrix}  H \\  | \end{smallmatrix}}{\mathop{C}}}\,-\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\overset{\begin{smallmatrix}  H \\  | \end{smallmatrix}}{\mathop{C}}}\,-H\xrightarrow{Conc.\,{{H}_{2}}S{{O}_{4}}}\]\[H-\overset{\begin{smallmatrix}  H \\  | \end{smallmatrix}}{\mathop{C}}\,=\overset{\begin{smallmatrix}  H \\  | \end{smallmatrix}}{\mathop{C}}\,-H+{{H}_{2}}O\]

    C)  Glucose is a monosaccharide sugar

    D)  Fructose is a disaccharide sugar

    Correct Answer: D

    Solution :

                     Fructose is a monosaccharide sugar because it does not hydrolysed further. All other options are correct.


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