A) \[n=3,l=2,m=+1,s=+\frac{1}{2}\]
B) \[n=4,l=1,m=0,s=+\frac{1}{2}\]
C) \[n=3,l=3,m=+3,s=+\frac{1}{2}\]
D) \[n=4,l=1,m=-1,s=+\frac{1}{2}\]
Correct Answer: C
Solution :
For 4p orbital, \[n=4\]and\[l=1\] and for 3d orbital, \[n=3\]and\[l=2\] So, option doesn't show 4p and 3d orbital, it indicates\['3f'\]orbital which is not possible.You need to login to perform this action.
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