BHU PMT BHU PMT (Screening) Solved Paper-2008

  • question_answer
    Assertion : Silica is soluble in HF. Reason (R): \[Si{{O}_{2}}+4HF\xrightarrow[{}]{{}}Si{{F}_{4}}+2{{H}_{2}}O\]                        \[Si{{F}_{4}}+2HF\xrightarrow[{}]{{}}{{H}_{2}}Si{{F}_{6}}\]

    A)  A and R both are correct and R is the correct explanation of A.

    B)  A and R both are correct but R is not the correct explanation of A.

    C)  A and R both are incorrect.

    D)  A is correct while R is incorrect.

    Correct Answer: B

    Solution :

                     Silica is soluble in HF. \[Si{{O}_{2}}\]reacts with HF to give\[Si{{F}_{4}}\]if HF is present in excess it gives\[{{H}_{2}}Si{{F}_{6}}\]. \[Si{{O}_{2}}+4HF\xrightarrow[{}]{{}}Si{{F}_{2}}+2{{H}_{2}}O\] \[Si{{F}_{4}}+2HF\xrightarrow[{}]{{}}{{H}_{2}}Si{{F}_{6}}\]           hydrofluoro silicic acid So, assertion and reason both are correct but reason is not the correct explanation of assertion.


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