A) \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow[{}]{B{{r}_{2}}/KOH}\]
B) \[C{{H}_{3}}CN\xrightarrow[{}]{LiAl{{H}_{4}}}\]
C) \[C{{H}_{3}}NC\xrightarrow[{}]{LiAl{{H}_{4}}}\]
D) \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow[{}]{LiAl{{H}_{4}}}\]
Correct Answer: C
Solution :
Isocyanide on reduction with\[LiAl{{H}_{4}}\] is presence of ether give secondary amine. \[C{{H}_{3}}NC+2{{H}_{2}}\xrightarrow[ether]{LiA{{H}_{4}}}\underset{{{2}^{o}}\,a\min e}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{N}}\,-H}}\,\]
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