A) \[n=1,l=1,{{m}_{l}}=1,{{m}_{s}}=+\frac{1}{2}\]
B) \[n=1,l=0,{{m}_{l}}=0,{{m}_{s}}=+\frac{1}{2}\]
C) \[n=2,l=1,{{m}_{l}}=1,{{m}_{s}}=-\frac{1}{2}\]
D) \[n=2,l=0,{{m}_{l}}=0,{{m}_{s}}=+\frac{1}{2}\]
Correct Answer: A
Solution :
If \[n=1,\]then\[l=0,\]because 1= zero to\[(n-1)\]any integral value. So, value of I never be equal to n. \[m=-l\] to +1 including zero So, if\[l=0,\] m never be equal to 1 Hence, the given set of quantum number is not applicable. \[n=1,l=1,{{m}_{1}}=1,{{m}_{s}}=+\frac{1}{2}\]
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