BHU PMT BHU PMT (Screening) Solved Paper-2009

  • question_answer
    The average power dissipation in pure inductance is

    A)  \[\frac{1}{2}L{{I}^{2}}\]               

    B)  \[2L{{I}^{2}}\]

    C)  \[\frac{1}{4}L{{I}^{2}}\]                               

    D)  zero

    Correct Answer: D

    Solution :

                     The average of instantaneous power in an AC circuit over a full cycle is called average power. It's unit is watt. \[{{P}_{av}}={{V}_{rms}}{{I}_{rms}}\cos \phi \] In a pure inductance, phase difference between voltage and current\[\phi ={{90}^{o}}\]. Power factor\[\cos \phi =0\] \[\therefore \]  Power\[P=0\]


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