A) \[\frac{V}{n}\]
B) \[nV\]
C) \[n{{V}^{2}}\]
D) \[{{n}^{2/3}}V\]
Correct Answer: D
Solution :
Suppose we have n identical drops each having radius r, capacitance C, charge q and potential V. If these drops are combined to form a big drop of radius R, capacitance C', charge Q and potential V will be become: Charge on big drop\[Q=nq\]. Capacitance of big drop \[C'={{n}^{1/3}}C\] Hence potential of big drop \[V'=\frac{Q}{C'}=\frac{nq}{{{n}^{1/3}}C}={{n}^{2/3}}V\]
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