question_answer

A particle of mass m moves in a circular path radius r under the action of a force\[\frac{m{{v}^{2}}}{r}\]. The work done during its motion over half of the circumference of the circular path will be

A)  \[\left( \frac{m{{v}^{2}}}{r} \right)\times 2\pi r\]             

B)  \[\left( \frac{m{{v}^{2}}}{r} \right)\times \pi r\]

C)  \[\frac{(2\pi r)}{\left( \frac{m{{v}^{2}}}{r} \right)}\]                       

D)  zero