A) \[A{{g}^{+}}\]
B) \[C{{u}^{2+}}\]
C) \[C{{d}^{2+}}\]
D) \[P{{b}^{2+}}\]
Correct Answer: D
Solution :
Ammonia is a Lewis base. It forms complexes with transition elements like\[A{{g}^{+}},C{{u}^{2+}}\]and\[C{{d}^{2+}}\]while it does not form complex with\[P{{b}^{2+}}\]because Pb is not a transition element. \[AgCl+2N{{H}_{4}}OH\xrightarrow[{}]{{}}[Ag{{(N{{H}_{3}})}_{2}}]Cl+2{{H}_{2}}O\] \[CuS{{O}_{4}}+4N{{H}_{4}}OH\to [Cu{{(N{{H}_{3}})}_{4}}]S{{O}_{4}}+4{{H}_{2}}O\] \[CdS{{O}_{4}}+4N{{H}_{4}}OH\to [Cu{{(N{{H}_{3}})}_{4}}]S{{O}_{4}}+4{{H}_{2}}O\]
You need to login to perform this action.
You will be redirected in
3 sec
