A) \[N{{O}_{2}}\]
B) \[Mn{{O}_{2}}\]
C) \[Ba{{O}_{2}}\]
D) \[S{{O}_{2}}\]
Correct Answer: C
Solution :
Barium peroxide\[(Ba{{O}_{2}})\]is an example of a true peroxide because it contains peroxide ion\[(O_{2}^{2-})\]or\[{{\left[ -O-O- \right]}^{2-}}\]and gives\[{{H}_{2}}{{O}_{2}}\]when reacts with acids. \[Ba{{O}_{2}}+{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}BaS{{O}_{4}}+{{H}_{2}}{{O}_{2}}\]
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