BHU PMT BHU PMT (Screening) Solved Paper-2010

  • question_answer
    The magnetic moment produced in a substance of 1 g is\[6\times {{10}^{-7}}A-{{m}^{2}}\]. If its density is\[5g/c{{m}^{3}},\]then the intensity of magnetization in A/m will be

    A)  \[8.3\times {{10}^{6}}\]               

    B)  3.0

    C)  \[1.2\times {{10}^{-7}}\]             

    D) \[3\times {{10}^{-6}}\]

    Correct Answer: B

    Solution :

                     The intensity of magnetization \[I=\frac{M}{V}=\frac{M}{mass\text{ }/\text{ }density}\] Given, mass\[=1\text{ }g={{10}^{-3}}kg\] and density\[=5g/c{{m}^{2}}\]                                 \[=\frac{5\times {{10}^{-3}}kg}{{{({{10}^{-2}})}^{3}}{{m}^{3}}}\]                                 \[=5\times {{10}^{3}}kg/{{m}^{3}}\]                                 \[I=\frac{6\times {{10}^{-7}}\times 5\times {{10}^{3}}}{{{10}^{-3}}}=3A/m\]


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