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BHU PMT BHU PMT (Screening) Solved Paper-2010

  • question_answer
    A body of mass M at rest explodes into three pieces, two of which of mass\[\frac{M}{4}\]each are thrown off in perpendicular directions with velocities of 3 m/s and 4 m/s respectively. The third piece will be thrown off with velocity of

    A)  1.5 m/s

    B)  2.0 m/s

    C)  2.5 m/s               

    D)  3.0 m/s

    Correct Answer: C

    Solution :

                     Momentum of one piece \[=\frac{m}{4}\times 3\] Again, momentum of one piece\[=\frac{m}{4}\times 4\] Resultant momentum\[=\sqrt{\frac{9{{M}^{2}}}{16}+{{M}^{2}}}\]                                                 \[=\frac{5M}{4}\] The third piece should also have the same momentum. Let its velocity be v, then                                 \[\frac{5M}{4}=\frac{M}{2}\times v\] or            \[v=\frac{5}{2}=2.5\,m/s\]


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