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BHU PMT BHU PMT (Screening) Solved Paper-2010

  • question_answer
    A\[500\mu F\]capacitor is charged at the steady rate of\[100\mu C/s\]. How long will it take to raise the potential difference between the plates of the capacitor to 10 V?

    A)  5s                                          

    B)  10s

    C)  50s                                       

    D)  100s

    Correct Answer: C

    Solution :

                    Charge, \[Q=CV=500\mu F\times 10V=5\times {{10}^{-3}}C\] Now,     \[Q=qt\]or \[t=\frac{Q}{q}\] Or           \[t=\frac{5\times {{10}^{-3}}}{100\times {{10}^{-6}}}s\]                 \[=\frac{1}{20}\times 1000\,s=50\,s\]


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