BHU PMT BHU PMT (Screening) Solved Paper-2010

  • question_answer
    Sickle cell anaemia is due to

    A)  change of amino acid in \[\text{ }\!\!\alpha\!\!\text{ -}\]chain of haemoglobin

    B)  change of amino add in \[\text{ }\!\!\beta\!\!\text{ -}\]chain of haemoglobin

    C)  change of amino acid in both \[\text{ }\!\!\alpha\!\!\text{ -}\] and \[\text{ }\!\!\beta\!\!\text{ -}\] chains of haemoglobin

    D)  change of amino acid in either \[\text{ }\!\!\alpha\!\!\text{ -}\] or \[\text{ }\!\!\beta\!\!\text{ -}\] chain of haemoglobin

    Correct Answer: B

    Solution :

                     The sixth amino acid from the amino terminal end of \[\text{ }\!\!\beta\!\!\text{ -}\]chain of normal haemoglobin is glutamic acid while in sickle cell haemoglobin, it is valine. It results a change in confirmation of the haemoglobin molecule and the RBC becomes sickle shaped.


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