A) 50
B) 5
C) 500
D) More than 5 million
Correct Answer: B
Solution :
Let n be the number of photons falling per second on the retina; then \[nhv=1.7\times {{10}^{-18}}\] Or \[\frac{nhc}{\lambda }=1.7\times {{10}^{-18}}\] Or \[n=\frac{1.7\times {{10}^{-18}}\times \lambda }{hc}\] \[=\frac{1.7\times {{10}^{-18}}\times 6000\times {{10}^{-10}}}{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}\] \[=5.15\approx 5\]
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