A) parallel to principal axis
B) convergent
C) divergent
D) None of the above
Correct Answer: A
Solution :
Power of system \[=\frac{1}{{{f}_{1}}}+\frac{1}{{{f}_{2}}}-\frac{d}{{{f}_{1}}{{f}_{2}}}\] \[=\frac{1}{1}+\frac{1}{-0.25}-\frac{0.75}{(1)(-0.25)}\] \[=1-4+\text{ }3=-3+\text{ }3=0\] Since, power of the system is zero therefore, the incident parallel beam of light will remain parallel after emerging from the system.
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