A) 2
B) 10
C) 4
D) 5
Correct Answer: D
Solution :
From Dalton's law, final pressure of the mixture of nitrogen and oxygen \[{{p}_{mix}}={{p}_{1}}+{{p}_{2}}\] \[=\frac{{{\mu }_{1}}RT}{V}+\frac{{{\mu }_{2}}RT}{V}\] \[=\frac{{{m}_{1}}}{{{M}_{1}}}\frac{RT}{V}+\frac{{{m}_{2}}}{{{M}_{2}}}\frac{RT}{V}\] \[=\frac{8}{32}\frac{RT}{V}+\frac{7}{28}\frac{RT}{V}=\frac{RT}{2V}\] \[10=\frac{RT}{2V}\] ??? (i) When oxygen is absorbed then for nitrogen by pressure \[p=\frac{7}{28}\frac{RT}{V}\] \[p=\frac{RT}{4V}\] ?????.. (ii) From Eqs. (i) and (ii), we get Pressure of the nitrogen\[p=5\text{ }atm\]
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