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BHU PMT BHU PMT (Screening) Solved Paper-2010

  • question_answer
    An ideal gas heat engine operates in Carnot cycle between\[227{}^\circ C\]and\[127{}^\circ C\]. It absorbs \[6\times {{10}^{4}}\]cal of heat at higher temperature. Amount of heat converted to work is

    A)  \[2.4\times {{10}^{4}}\text{ }cal\]           

    B) \[6\times {{10}^{4}}\text{ }cal\]

    C)  \[1.2\times {{10}^{4}}cal\]         

    D) \[4.8\times {{10}^{4}}\text{ }cal\]

    Correct Answer: C

    Solution :

                     Efficiency, \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}=\frac{W}{Q}\] \[W=\frac{Q({{T}_{1}}-{{T}_{2}})}{{{T}_{2}}}\] \[=\frac{6\times {{10}^{4}}[(227+273)-(127+273)]}{(227+273)}\] \[=\frac{6\times {{10}^{4}}\times 100}{500}=1.2\times {{10}^{4}}cal\]


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