A) \[-\frac{a}{2b}\]
B) \[+\frac{a}{2b}\]
C) \[-\frac{a}{b}\]
D) \[+\frac{a}{b}\]
Correct Answer: C
Solution :
At temperature of inversion E is minimum, ie, \[E=0\] \[E=at+b{{t}^{2}}\] \[\therefore \] \[0=a{{t}_{i}}+bt_{i}^{2}\] Or \[{{t}_{i}}=-\frac{a}{b}\]
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