A) \[C{{H}_{2}}Cl-CHDBr\]
B) \[C{{H}_{3}}CHC{{l}_{2}}\]
C) \[C{{H}_{3}}CHDCl\]
D) \[C{{H}_{2}}H-CHClC{{H}_{3}}\]
Correct Answer: B
Solution :
Chirality (ie, presence of asymmetric carbon atom) is the necessity for exhibiting optical activity. Thus,\[C{{H}_{3}}CHC{{l}_{2}},\]because of the lack of asymmetric carbon atom, does not exhibit optical isomerism.
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