A) \[\frac{7M{{L}^{2}}}{48}\]
B) \[\frac{M{{L}^{2}}}{9}\]
C) \[\frac{M{{L}^{2}}}{12}\]
D) \[\frac{M{{L}^{2}}}{3}\]
Correct Answer: B
Solution :
The moment of inertia about middle point \[{{I}_{CM}}=\frac{M{{L}^{2}}}{12}\] From theorem of parallel axis theorem \[\therefore \] \[I={{I}_{CM}}+M{{x}^{2}}=\frac{M{{L}^{2}}}{12}+M{{\left( \frac{L}{6} \right)}^{2}}\] \[=\frac{M{{L}^{2}}}{9}\]You need to login to perform this action.
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