A) 90.2m
B) 89.6m
C) 86.6m
D) 70.2m
Correct Answer: C
Solution :
Total time of flight \[=\frac{2u\sin \theta }{g}\] \[=\frac{2\times 50\times 1}{2\times 10}=5\,s\] Time to cross the wall\[=3\text{ }s\] (given) Time in air after crossing the wall \[=(5-3)=2\text{ }s\] \[\therefore \] Distance travelled beyond the wall \[=(u\cos \theta )t\] \[=50\times \frac{\sqrt{3}}{2}\times 2\] \[=86.6\text{ }m\]You need to login to perform this action.
You will be redirected in
3 sec