question_answer

The STP volume of oxygen liberated by 2 A of current when passed through acidulated water for 3 min and 13 s is

A)  120 cc                                  

B)  22.4 cc

C)   11.2cc                                 

D)  44.8 cc

Correct Answer: B

Solution :

                 \[2{{H}_{2}}O4{{H}^{+}}+2{{O}^{2-}}\] \[\because \]\[4\times 96500\text{ }C\]electricity liberate\[{{O}_{2}}\] \[=22400\text{ }cc\] \[\therefore \]\[(2\times 193)C\]electricity will liberate\[{{O}_{2}}\]                                                 \[=\frac{22400\times 386}{4\times 96500}\] \[=22.4cc\]