A) \[2\pi \sqrt{\frac{3L}{2g}}\]
B) \[\pi \sqrt{\frac{3L}{g}}\]
C) \[2\pi \sqrt{\left( \frac{3L}{g} \right)}\]
D) \[2\pi \sqrt{\frac{2L}{g}}\]
Correct Answer: A
Solution :
The effective acceleration in a lift descending with acceleration \[\frac{g}{3}\] is \[{{g}_{eff}}=g-\frac{g}{3}=\frac{2g}{3}\] Time period of simple pendulum \[\therefore \] \[T=2\pi \sqrt{\frac{L}{{{g}_{eff}}}}\] \[=2\pi \sqrt{\frac{L}{2g/3}}\] \[=2\pi \sqrt{\frac{3L}{2g}}\]
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