A) four
B) two
C) one
D) three
Correct Answer: C
Solution :
The coordination number of Pt metal is 6, ie, it will get coordinated with six monodentate ligands. Since, here only\[3N{{H}_{3}}\]ligands are present, thus it gets coordinated to three\[N{{H}_{3}}\] ligands and three\[C{{l}^{-}}\]ligands. Hence, only one\[C{{l}^{-}}\]is present outside the coordination sphere, ie, ionisable.\[[Pt{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]Cl\].
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