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BHU PMT BHU PMT (Screening) Solved Paper-2010

  • question_answer
    \[A\xrightarrow[{{H}_{2}}S{{O}_{4}}]{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}B\xrightarrow[\begin{smallmatrix}  Vigorous \\  oxidation \end{smallmatrix}]{[O]}C{{H}_{3}}COOH\]If B in the given sequence is propanone then A is

    A)  ethyl alcohol

    B)  iso-propyl alcohol

    C)  propyl alcohol

    D)  tert-pentyl alcohol

    Correct Answer: B

    Solution :

                     Secondary alcohols upon oxidation give ketones with the same number of carbon atoms. Thus, A is iso-propyl alcohol and the reactions are as \[\underset{{}}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix}  || \\  O \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\,\xrightarrow[{}]{{{K}_{2}}C{{r}_{2}}{{O}_{7}}/{{H}_{2}}S{{O}_{4}}}\]                 \[\underset{propanone}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix}  || \\  O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}}}\,\xrightarrow[\begin{smallmatrix}  Vigorous \\  oxidation \end{smallmatrix}]{[O]}C{{H}_{3}}COOH\]


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