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BHU PMT BHU PMT (Screening) Solved Paper-2010

  • question_answer
    If for\[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}{{H}_{2}}O(g),\]\[\Delta {{H}_{1}}\]is the enthalpy of reaction and fo\[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}{{H}_{2}}O(l)\]\[\Delta {{H}_{2}}\]is enthalpy of reaction, then

    A)  \[\Delta {{H}_{1}}>\Delta {{H}_{2}}\]     

    B) \[\Delta {{H}_{1}}=\Delta {{H}_{2}}\]

    C)  \[\Delta {{H}_{1}}<\Delta {{H}_{2}}\]    

    D) \[\Delta {{H}_{1}}+\Delta {{H}_{2}}=0\]

    Correct Answer: C

    Solution :

                     In the process,\[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}{{H}_{2}}O(l),\]heat is evolved because state is changing from gaseous to liquid, ie, the process is exothermic. Hence,    \[\Delta {{H}_{1}}<\Delta {{H}_{2}}\]


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