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BHU PMT BHU PMT (Screening) Solved Paper-2010

  • question_answer
    A sodium cation has a different number of electrons from

    A)  \[{{O}^{2-}}\]                                   

    B) \[{{F}^{-}}\]

    C)   \[L{{i}^{+}}\]                                   

    D) \[A{{l}^{3+}}\]

    Correct Answer: C

    Solution :

                     
    Species Number of electrons
    \[N{{a}^{+}}\] \[(11-1)=10\]
    \[{{O}^{2-}}\] \[(8+2)=10\]
    \[{{F}^{-}}\] \[(9+1)=10\]
    \[L{{i}^{+}}\] \[(3-1)=2\]
    \[A{{l}^{3+}}\] \[(13-3)=10\]
    Thus,\[N{{a}^{+}}\]has different number of electrons from\[L{{i}^{+}}\].


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