A) \[SO_{3}^{2-}\]
B) \[SO_{4}^{2-}\]
C) \[{{S}_{4}}O_{6}^{2-}\]
D) \[{{S}_{2}}O_{5}^{2-}\]
Correct Answer: C
Solution :
Iodine oxidises thiosulphate ion into tetrathionate ion. \[\underset{\begin{smallmatrix} thiosulphate \\ \,\,\,\,\,\,ion \end{smallmatrix}}{\mathop{2{{S}_{2}}O_{3}^{2-}}}\,+{{I}_{2}}\xrightarrow{{}}\underset{\begin{smallmatrix} tetrathionate \\ \,\,\,\,\,\,\,\,ion \end{smallmatrix}}{\mathop{{{S}_{4}}O_{6}^{2-}}}\,+2{{I}^{-}}\]
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