A) \[C{{H}_{3}}C{{H}_{2}}CH(OH)C{{H}_{3}}\]
B) \[{{(C{{H}_{3}})}_{2}}CH\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,{{C}_{2}}{{H}_{5}}\]
C) \[C{{H}_{3}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-OC{{H}_{3}}\]
D) \[{{(C{{H}_{3}})}_{2}}CHC{{H}_{2}}OH\]
Correct Answer: A
Solution :
Alcohols having\[C{{H}_{3}}CH(OH)\]group and ketones having\[C{{H}_{3}}CO\]group give iodoform when warmed with\[NaOH\]and 12. Thus, only\[C{{H}_{3}}C{{H}_{2}}CH(OH)C{{H}_{3}}\] gives iodoform on warming with\[NaOH\]and\[{{I}_{2}}\].
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